*Eyy...everyone.....Ivy would like to tell all the 40s Applied Math student... what happened or what she've learned today....*We only have one class...but sure do my brain almost explode in what we have for the group problem...but anywaysss...

Mr. K gave us some matricies question.. about connectivity matrix at the

*of our class....yesterday i was pretty confused about it.. but i finally got it when Shane actually explain it to me...*

**first part***is about our text book assignment...Mr. K asked us about any problems we encounter by doing the textbook questions...and so he explained some problems that we didn't get.*

**Second part**

**The Group Problem**WE did this problem about 6 guys doing the activity of ski jump. It has the number of points that those guys got and the difficulties. The question is....how can we explain by multiplying the points and the difficulties by making a matrix model; also to find who got the greatest points and the least. How can we do that?

Guy 1 - 24.3 27.5 27.1 21.4

Guy 2 - 21.2 24.2 18.3 15.2

Guy 3 - 21.3 21.8 15.9 21.5

Guy 4 - 18.7 27.2 21 18.6

Guy 5 - 24.4 24.2 21.4 24.5

Guy 6 - 27.6 18.3 21.6 21.5

^ What you See on top is the ski-jumpers points.^

I 1.4 1.5 1.3 1.6 1.5 1.2

II 1.6 1.4 1.7 1.4 1.6 1.5

III 1.5 1.9 1.9 2.0 1.9 1.7

IV 1.7 2.1 1.4 1.8 2.0 1.9

^ What you See on top is the Ski-jumpers difficulties.^

It's also asking us which way is the better idea to multiply the points and difficulties. Lets give a names to this two data of the ski-jumpers.in matricies.. Let be Points = A and Difficulties = B. So which way is better?

[A] is (6x4)

[B] is (4x6)

THEY CAN BE SOLVE IN BOTH WAYS. butttttttt........which is the right one????

**SOLUTION**Lets put it this way [a] x [b] = THE PRODUCT. So if [A] got rows and columns by 6x4 and [B] got 4x6 it can be solve...and our product should have 6x6 in rows and columns. We are solving it this way because we need to find all the total points for each ski-jumpers and it's possible to do this way, yes they do have different types of difficulties in each jumpers but in order to be fair we need to multiply them with the different numbers of the other ski-jumpers. NOW if we got all the product by multiplying [A] x [B] in matrix..thenn...to add up all the total points of the ski-jumpers we need to multiply the product with "1" that has 6x1 rows and columns...

We don't add the following individualy because it's going to take time, by multiplying with "1" in 6x1 we should have the ski-jumpers total...and see who got the most points and least.

<<------------------------->>

[A] x [B] = THE PRODUCT

[ PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT] [ 1 ]

[ PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT] [ 1 ]

[ PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT] [ 1 ]

[ PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT] [ 1 ]

[ PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT] [ 1 ]

[ PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT PRODUCT] [ 1 ]

<<-------------------------->>

AND THAT'S THE CASE!!! HOPE I DIDN"T CONFUSE YOU........

**Monday's Scribe (Feb. 13, 2006) is going to be : Corrie.**I'm sorry for the person that i chose... i barely know everyone in this class...

Way to go Ivy! That

wasa tough problem. You worked really hard on this scribe post and it shows!A job well done!

Posted by Mr. Kuropatwa | 2/12/2006 11:17 PM

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